document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=729557>Question 729557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you determine the length and width when you are given the difference of two similar objects </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446102 by </B><A HREF=/tutors/aboutme.mpl?userid=lynnlo><B>lynnlo(4176)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lynnlo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2L+2W<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "P/2=L+W<BR>\n" );
document.write( "IF THE PERIMETER IS GIVEN AND YOU KNOW ONE OF THE SIDES MEASURE LENGTH,THEN YOU CAN FIND THE MEASURE LENGTH OF THE SIDES,IF YOU KNOW THE MEASURE LENGTH OF L,THEN MEASURE LENGTH OF W IS P/2=W AND \"VICE VERSA </SPAN>\n" );
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