document.write( "Question 729601: 10 men can do a piece of work in 24 days. After working 6 days,few men were added to finish the work in 21 days from the begining. Find the added men. \n" ); document.write( "

Algebra.Com's Answer #446100 by Edwin McCravy(20056) $\"\"$ $\"About$

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10 men can do a piece of work in 24 days. After working 6 days, a few men were added to finish the work in 21 days from the begining. Find the added men.
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document.write( ">>...10 men can do a piece of work in 24 days...<<  \r\n" );
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document.write( "So the 10 men's combined working rate is  or .  \r\n" );
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document.write( "Also it would take 1 man 240 days (ten times as long as it would take 10\r\n" );
document.write( "men.  So 1 man's working rate is  or . \r\n" );
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\n" ); document.write( ">>...After working 6 days,...<<
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document.write( "In those 6 days the 10 men at the rate of  have done\r\n" );
document.write( "{6/24}}}ths or th of job and so there is still ths of the job\r\n" );
document.write( "left to be done.  \r\n" );
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\n" ); document.write( ">>...A few men were added to finish the work in 21 days from the begining...<<
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document.write( "Let the number of men added be N.  So for the remaining 21-6 or 15 days,\r\n" );
document.write( "we have 10+N men working at the combined rate of (10+N)·\r\n" );
document.write( "or  or  doing ths of the job.\r\n" );
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document.write( "So 15 days times their  rate should equal ths of the job.\r\n" );
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document.write( "                               \r\n" );
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document.write( "Cross multiply:\r\n" );
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document.write( "                                 60(10+N) = 3·240\r\n" );
document.write( "                                 60 + 60N = 720\r\n" );
document.write( "                                      60N = 660\r\n" );
document.write( "                                        N = 11 \r\n" );
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document.write( "So they added 11 men.\r\n" );
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document.write( "Edwin

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