document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=729600>Question 729600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> car A left dagupan at 9:00 am going to manila with a velocity of 40km/hr. <BR>\n" );
document.write( "after 1hr,car B left from the same location and taken the same route as car A going to manila. if car B has a velocity of 90km/hr, what time does car B over take car A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446048 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First car	40	mph				<BR>\n" );
document.write( "Car II	90	mph				<BR>\n" );
document.write( "First car		09:00				<BR>\n" );
document.write( "Car II		10:00				<BR>\n" );
document.write( "Difference in time=		01:00	=>	1.00	hours	<BR>\n" );
document.write( "First car	will have covered	40.00	miles		Car II	starts<BR>\n" );
document.write( "catch up distance=		40.00	miles			<BR>\n" );
document.write( "catch up speed =		90	-40			<BR>\n" );
document.write( "catch up speed =		50	mph			<BR>\n" );
document.write( "Catchup time = catchup distance/catch up speed						<BR>\n" );
document.write( "catch up time=		0.8				<BR>\n" );
document.write( "catch up time=		0.80	hours	=48 minutes		<BR>\n" );
document.write( "They will meet at		10:48	pm		<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );