document.write( "Question 729598: what does -x+1x equal?
\n" ); document.write( "I am trying to solve an equation with this in it....just trying to combine like terms thats all
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Algebra.Com's Answer #446045 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"1x=x\"
\n" ); document.write( "\"-1x=-x\"
\n" ); document.write( "We do not usually take the trouble to write the 1 and -1 in front of x as visible coefficients.
\n" ); document.write( "You could think of it as
\n" ); document.write( "\"-x%2B1x=-1x%2B1x=%28-1%2B1%29x=0%2Ax=0\"
\n" ); document.write( "Maybe you could just write
\n" ); document.write( "\"-x%2B1x=-x%2Bx=0\" or even shorter as \"-x%2B1x=-x%2Bx=0\"
\n" ); document.write( "The question is how much writing does your teacher expect.
\n" ); document.write( "Are you expected to write more baby steps that seems obvious to me and your teacher just to show that you understand what you are doing?
\n" ); document.write( "Or would the extra steps just seem ridiculous and annoying to your teacher?
\n" ); document.write( "If you had more than a couple of weeks of algebra classes, I would not want to see extra steps.
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\n" ); document.write( "MY UNDERSTANDING OF ALGEBRA:
\n" ); document.write( "Subtraction does not really exist. It is just a reflection of addition, just like the trees you see inside the water on a still pond are just the reflection of trees on the ground next to the pond.
\n" ); document.write( "A negative number means just go in the other direction.
\n" ); document.write( "5-3 is really 5 + (-3) , which could mean go miles North and them go 3 miles South.
\n" ); document.write( "Each variable has a coefficient (a number in front of the variable) even if you do not see one.
\n" ); document.write( "x-3x means really 1x + (-3)x, which could mean 1 mile North, then 3 miles South, or one small step North, then 3 small steps South, or deposit one dollar in the bank account, then withdraw 3 dollars. It does not matter what x means, I can add up all the x together.
\n" ); document.write( "I do not write more than needed, it just write x-3x=-2x, although I understand that x is 1 times x, -3x is (-3) times x, and they are added so I get (-2) times x.
\n" ); document.write( "If you ever see a minus sign in front of a parenthesis, as in
\n" ); document.write( "2(x-5)-(x+2) try to see an invisible 1.
\n" ); document.write( "It is really 2(x + (-5)) + (-1)(x + 2)= 2x + 2(-5) + (-1)x + (-1)2 = 2x + (-10) + (-1)x + (-2)
\n" ); document.write( "The result is 2x + (-10) + (-1)x + (-2), which I write as 2x-10-x-2 .
\n" ); document.write( "Next I collect like terms, understanding that what I am doing is rearranging the pieces I am adding and that in baby steps is
\n" ); document.write( "2x + (-10) + (-1)x + (-2) = (2x + (-1)x) + ((-10) + (-2)) = (2 + (-1))x + (-12) = 1x + (-12)
\n" ); document.write( "I write that final result as just x-12.
\n" ); document.write( "I write the whole calculation as
\n" ); document.write( "2(x-5)-(x+2) = 2x-10-x-2 = x-12 ,
\n" ); document.write( "but I understand that I am working with adding and multiplying positive and negative numbers, some of which are multiplied times x, and since no one has given me a value for x, I have to keep the x stuff separated from the stuff that does not have x (as if it were in separate accounts).
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