document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=729529>Question 729529</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Working together, it takes two computers 15 minutes to send out a company’s email. If it takes the slower computer 60 minutes to do the job on its own, how long will it take the faster computer to do the job on its own? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #446043 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=446043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Working together, it takes two computers 15 minutes to send out a company’s email. If it takes the slower computer 60 minutes to do the job on its own, how long will it take the faster computer to do the job on its own?<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = time (minutes) it takes faster computer to do job alone<BR>\n" );
document.write( "then<BR>\n" );
document.write( "15(1/x + 1/60) = 1<BR>\n" );
document.write( "multiplying both sides by 60x:<BR>\n" );
document.write( "15(60 + x) = 60x<BR>\n" );
document.write( "900 + 15x = 60x<BR>\n" );
document.write( "900 = 45x<BR>\n" );
document.write( "20 minutes = x<BR>\n" );
document.write( " </SPAN>\n" );
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