document.write( "Question 729496: An investor invested a total of 2400.oo in two mutual funds. One fund earned a 4%and the other earned a 2% profit. If the investor's total profit was 86.00, how much was invested in each mutual fund? \n" ); document.write( "

Algebra.Com's Answer #446017 by mananth(16946) $\"\"$ $\"About$

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Part I 4.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 2.00% per annum ------------ Amount invested = y
\n" ); document.write( " 2400
\n" ); document.write( "Interest----- 86
\n" ); document.write( "
\n" ); document.write( "Part I 4.00% per annum ---x
\n" ); document.write( "Part II 2.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 2400 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "4.00% x + 2.00% y= 86
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4 x + 2 y= 8600.00 --------2
\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
\n" ); document.write( "-4 x -4 y= -9600.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -2 y= -1000
\n" ); document.write( "divide by -2
\n" ); document.write( " y = 500
\n" ); document.write( "Part I 4.00% $ 1900
\n" ); document.write( "Part II 2.00% $ 500
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "1900 --------- 4.00% ------- 76.00
\n" ); document.write( "500 ------------- 2.00% ------- 10.00
\n" ); document.write( "Total -------------------- 86.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

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