document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=729498>Question 729498</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular field is 188 yards. If the length of the field is 81 yards, what is its width?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #445909 by </B><A HREF=/tutors/aboutme.mpl?userid=lynnlo><B>lynnlo(4176)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lynnlo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=445909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> PERIMETER===================188YDS.<BR>\n" );
document.write( "LENGTH========================81YDS. <BR>\n" );
document.write( "(1)FORMULA (2)IDENTIFY (3)PLUG-IN (4)SOLVE <BR>\n" );
document.write( "P=2L+2W<BR>\n" );
document.write( "188=2(81)+2W             P=188YDS.<BR>\n" );
document.write( "                          L=81<BR>\n" );
document.write( "188=162+2W<BR>\n" );
document.write( " -162 -162                W=?<BR>\n" );
document.write( "188-162=2W<BR>\n" );
document.write( "26/2=2W/2<BR>\n" );
document.write( "W=13 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );