document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=729293>Question 729293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 1 cm less than 3 times the width. The rectangle has an area of 24 square cm. find the exact length of a diagonal of this rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #445827 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=445827\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = length<BR>\n" );
document.write( "y = width<BR>\n" );
document.write( "x = -1+3y<BR>\n" );
document.write( "d = diagonal\r<BR>\n" );
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document.write( "AREA, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283y-1%29y=24 ALIGN=MIDDLE  ALT=\"%283y-1%29y=24\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "FIND DIAGONAL, d.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%5E2=x%5E2%2By%5E2 ALIGN=MIDDLE  ALT=\"d%5E2=x%5E2%2By%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%5E2=%283y-1%29%5E2%2By%5E2 ALIGN=MIDDLE  ALT=\"d%5E2=%283y-1%29%5E2%2By%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=sqrt%28%283y-1%29%5E2%2By%5E2%29 ALIGN=MIDDLE  ALT=\"d=sqrt%28%283y-1%29%5E2%2By%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Using area equation, first find y.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3y%5E2-y=24 ALIGN=MIDDLE  ALT=\"3y%5E2-y=24\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3y%5E2-y-24=0 ALIGN=MIDDLE  ALT=\"3y%5E2-y-24=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "for practical purposes, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y=3%29 ALIGN=MIDDLE  ALT=\"highlight%28y=3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  (used general quadratic solution formula).\r<BR>\n" );
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document.write( "Using formula just found for d, diagonal, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=sqrt%28%283%2A3-1%29%5E2%2B3%2A3%29 ALIGN=MIDDLE  ALT=\"d=sqrt%28%283%2A3-1%29%5E2%2B3%2A3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28d=sqrt%2873%29%29 ALIGN=MIDDLE  ALT=\"highlight%28d=sqrt%2873%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, the Diagonal.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );