document.write( "Question 729303: Two dice are rolled in a game you pay $1.00 to play. If a total lower than 5 comes up, you win $5.00, if a total greater than 9 comes up you win $2.00, otherwise you lose your dollar for playing. Calculate the expected value of playing,and the price of the game making it fair.\r
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Algebra.Com's Answer #445809 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Two dice are rolled in a game you pay $1.00 to play.
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\n" ); document.write( "If a total lower than 5 comes up, you win $5.00,
\n" ); document.write( "ways to do that: 1/1,1/2,1/3,2/1,2/2,3/1 -----6 ways
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\n" ); document.write( "if a total greater than 9 comes up you win $2.00,
\n" ); document.write( "Ways to do that:
\n" ); document.write( "4/6----------------------1
\n" ); document.write( "5/5,5/6------------------2
\n" ); document.write( "6/4,6/5,6/6--------------3
\n" ); document.write( "Total-----------------------------------------6 ways
\n" ); document.write( "otherwise you lose your dollar for playing.
\n" ); document.write( "Total-----------------------------------------24 ways
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\n" ); document.write( "Calculate the expected value of playing,
\n" ); document.write( "Random Value:.....$4......$1......-1
\n" ); document.write( "Probabilities.....1/6.....1/6.....4/6
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\n" ); document.write( "Expected gain: (4 + 1 - 4)/6 = 1/6 or 16 2/3 cents
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\n" ); document.write( "and the price of the game making it fair.
\n" ); document.write( "You should pay $1.67 to play
\n" ); document.write( "Then your expected winning would be zero and the game would be fair.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H
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