document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=729014>Question 729014</A>: <I><SPAN STYLE=\"word-break: break-all;\"> True or False? And Why?\r<BR>\n" );
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document.write( "If P(E U F) = P(E) + P(F), what can be concluded about P(E and F)?\r<BR>\n" );
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document.write( "AND\r<BR>\n" );
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document.write( "P(A U B) - P(B) = P(A) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #445707 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=445707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If P(E U F) = P(E) + P(F), then P(E and F) must be zero since the more general formula is \r<BR>\n" );
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document.write( "P(E U F) = P(E) + P(F) - P(E and F)\r<BR>\n" );
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document.write( "The same applies to the second equation as well </SPAN>\n" );
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