document.write( "Question 63920This question is from textbook introductory and intermediate algebra
\n" ); document.write( ": m^2-8m+15=0 \n" ); document.write( "
Algebra.Com's Answer #44569 by praseenakos@yahoo.com(507)\"\" \"About 
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ANSWER:\r
\n" ); document.write( "\n" ); document.write( "m^2-8m+15=0\r
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\n" ); document.write( "\n" ); document.write( "This is a quadratic equation in the variable,' m'\r
\n" ); document.write( "\n" ); document.write( "WE CAN SOLVE THIS PROBLEM USING DIFFERENT METHODS.\r
\n" ); document.write( "\n" ); document.write( "1. SPLITTING MIDDLE TERMS\r
\n" ); document.write( "\n" ); document.write( "2. USING QUADRATIC FORMULA\r
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\n" ); document.write( "\n" ); document.write( "Lets take the first method,\r
\n" ); document.write( "\n" ); document.write( "m^2-8m+15=0, here we have coefficent of m is -8 and the consant term is +15\r
\n" ); document.write( "\n" ); document.write( "Find out two numbers so that their product(multiplication) is +15 and their sum is -8\r
\n" ); document.write( "\n" ); document.write( "such two numbers are -3 and -5\r
\n" ); document.write( "\n" ); document.write( "because -3* -5 = +15 and -3 + -5 = -8\r
\n" ); document.write( "\n" ); document.write( "Now split the middle term as follows,\r
\n" ); document.write( "\n" ); document.write( "m^2 - 5m - 3m + 15 = 0\r
\n" ); document.write( "\n" ); document.write( "Now group the terms as follows,\r
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\n" ); document.write( "\n" ); document.write( "(m^2 - 5m )- (3m - 15) = 0\r
\n" ); document.write( "\n" ); document.write( "Take out common terms from each group,\r
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\n" ); document.write( "\n" ); document.write( "m ( m - 5 ) - 3 ( m - 5 ) = 0\r
\n" ); document.write( "\n" ); document.write( "again (m-5) is common in both the groups, so take them out,\r
\n" ); document.write( "\n" ); document.write( "(m-5)(m -3) = 0\r
\n" ); document.write( "\n" ); document.write( "This implies, either (m-5) is equal to 0 or (m -3) = 0\r
\n" ); document.write( "\n" ); document.write( "If (m-5) = o \r
\n" ); document.write( "\n" ); document.write( "==> m = 5 and \r
\n" ); document.write( "\n" ); document.write( "If(m -3) =0 ==> m = 3\r
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\n" ); document.write( "\n" ); document.write( "Thos we got two values for m.\r
\n" ); document.write( "\n" ); document.write( "Whichj is the required solutions for the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Now lets take the second method,\r
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\n" ); document.write( "\n" ); document.write( "We have the quadratic formula, \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" for solving a standard quadratic equation, ax^2 + bx + c = 0\r
\n" ); document.write( "\n" ); document.write( "Compare this with our given equation,\r
\n" ); document.write( "\n" ); document.write( "then we have ,\r
\n" ); document.write( "\n" ); document.write( "a= 1, b = -8 and c= 15\r
\n" ); document.write( "\n" ); document.write( "substitute these values in the quadratic formula,\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" \r
\n" ); document.write( "\n" ); document.write( "\"m+=+%28-%28-8%29%2B-+sqrt%28+%28-8%29%5E2-4%2A1%2A15%29%29%2F%282%2A1%29+\" \r
\n" ); document.write( "\n" ); document.write( "\"m+=+%288+%2B-+sqrt%28+64-60+%29%29%2F%282%29+\" \r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%288+%2B-+sqrt%28+4%29%29%2F%282%29+\" \r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%288+%2B-+2%29%2F%282%29+\" \r
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\n" ); document.write( "\n" ); document.write( "That means m = (8 + 2)/(2) or m = (8 - 2)/(2)\r
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\n" ); document.write( "\n" ); document.write( "==> m = 10/2 or m = 6/2\r
\n" ); document.write( "\n" ); document.write( "==> m = 5 or m = 3\r
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\n" ); document.write( "\n" ); document.write( "Here also we got the same value.\r
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\n" ); document.write( "\n" ); document.write( "You can use any method which you find easier.\r
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\n" ); document.write( "\n" ); document.write( "Hope you understood.\r
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\n" ); document.write( "\n" ); document.write( "Regards.\r
\n" ); document.write( "\n" ); document.write( "praseenakos@yahoo.com\r
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