document.write( "Question 63898: If the sides of a square are increased by 3 inches, th area is increased by 39 in^2. What are the dimensions of the original square? \n" ); document.write( "
Algebra.Com's Answer #44568 by rahman(247)\"\" \"About 
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Suppose :
\n" ); document.write( "x is the original side of the square
\n" ); document.write( "L is area of the original square
\n" ); document.write( "Ln is area of the new square
\n" ); document.write( "so,
\n" ); document.write( "L = x^2
\n" ); document.write( "Ln = (x+3)^2
\n" ); document.write( "L + 39 = x^2+6x+9
\n" ); document.write( "x^2 + 39 = x^2+6x+9
\n" ); document.write( "39 = 6x + 9
\n" ); document.write( "39 - 9 = 6x
\n" ); document.write( "30 = 6x
\n" ); document.write( "5 = x\r
\n" ); document.write( "\n" ); document.write( "Conclude: the dimension of the original square is 5 inches x 5 inches
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