document.write( "Question 729054: the perimeter of a rectangle is 46 feet. the width is 3ft lees than twicw the length. find the lenght and width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #445678 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "W=2L-3 \n" ); document.write( "46=2L+2(2L-3) \n" ); document.write( "46=2L+4L-6 \n" ); document.write( "46+6=6L \n" ); document.write( "6L=52 \n" ); document.write( "L=52/6 \n" ); document.write( "L=8.67 FT. ANS. \n" ); document.write( "W=2*8.67-3 \n" ); document.write( "W=17.33-3 \n" ); document.write( "W=14.33 FT. ANS. \n" ); document.write( "PROOF: \n" ); document.write( "46=2*8.67+2*14.33 \n" ); document.write( "46=17.33+28.66 \n" ); document.write( "46=46 \n" ); document.write( " \n" ); document.write( " |