document.write( "Question 728863: I don't know how to solve this word problem. All I know is R*T=D. Please help me solve.\r
\n" );
document.write( "\n" );
document.write( "\"Traveling for 3 hours into a steady headwind a jet traveled 1650 miles. If the jet were flying with the same wind it could have gone 1300 miles in only 2 hours. Find the rate of the jet in calm air and the rate if the wind.\" \n" );
document.write( "
Algebra.Com's Answer #445646 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Plane speed =x mph \n" ); document.write( "wind speed =y mph \n" ); document.write( "against wind 3 hours \n" ); document.write( "with wind 2 hours \n" ); document.write( " \n" ); document.write( "Distance against 1650 miles distance with 1300 miles \n" ); document.write( "t=d/r against wind - \n" ); document.write( "1650 / ( x - y )= 3 \n" ); document.write( "3 ( x - y ) = 1650 \n" ); document.write( "3 x - 3 y = 1650 ....................1 \n" ); document.write( " \n" ); document.write( "1300 / ( x + y )= 2 \n" ); document.write( "2 ( x + y ) = 1300 \n" ); document.write( "2 x + 2 y = 1300 ...............2 \n" ); document.write( "Multiply (1) by 1 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "we get \n" ); document.write( "3 x + -3 y = 1650 \n" ); document.write( "2 x + 2 y = 1300 \n" ); document.write( "5 x = 2950 \n" ); document.write( "/ 5 \n" ); document.write( "x = 590.00 mph \n" ); document.write( " \n" ); document.write( "plug value of x in (1) y \n" ); document.write( "3 x -3 y = 1650 \n" ); document.write( "1770 -3 -1770 = 1650 \n" ); document.write( "-3 y = 1650 \n" ); document.write( "-3 y = -120 mph \n" ); document.write( " y = 40.00 \n" ); document.write( "Plane speed 590.00 mph \n" ); document.write( "wind speed 40.00 mph \n" ); document.write( " \n" ); document.write( " |