document.write( "Question 728864: A flight departs from a city A at 11:00 a.m. CST to arrive in city B at 2:30 p.m. MST. If the plane flies at an average rate of 413 1/2 mph, what distance does it travel? (Hint: There is a 1-hour time difference between CST and MST.) \n" ); document.write( "
Algebra.Com's Answer #445645 by mananth(16946)\"\" \"About 
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CST is 1 hour ahead of Mountain time\r
\n" ); document.write( "\n" ); document.write( "when it is 11.00 am CST it is actuall 10AM MST\r
\n" ); document.write( "\n" ); document.write( "10 to 2.30 = 4.5 hours\r
\n" ); document.write( "\n" ); document.write( "speed = 413.5 \r
\n" ); document.write( "\n" ); document.write( "distance = speed * time\r
\n" ); document.write( "\n" ); document.write( "= 1860.75 miles
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