document.write( "Question 63851: slove algebraically log5 + log (4-2x)= log(x-1) \n" ); document.write( "
Algebra.Com's Answer #44564 by rahman(247)\"\" \"About 
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log5 + log (4-2x)= log(x-1)
\n" ); document.write( "\"log+%285%2A%284-2x%29%29=log%28x-1%29\"
\n" ); document.write( "\"log+%2820-10x%29=log%28x-1%29\"
\n" ); document.write( "20-10x=x-1
\n" ); document.write( "20+1=10x+x
\n" ); document.write( "21=11x
\n" ); document.write( "\"x=21%2F11\"
\n" ); document.write( "ok
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