document.write( "Question 728889: qudratic formula (4x^2)+bx-3=0 slove for b. and one solution is -5/2 \n" ); document.write( "
Algebra.Com's Answer #445639 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
(4x^2)+bx-3=0 solve for b. and one solution is -5/2\r
\n" ); document.write( "\n" ); document.write( "if p & q are the roots of the equation\r
\n" ); document.write( "\n" ); document.write( "p+q=-b/4\r
\n" ); document.write( "\n" ); document.write( "let p=-5/2\r
\n" ); document.write( "\n" ); document.write( "(-5/2)+q=-b/4
\n" ); document.write( "multiply by 4
\n" ); document.write( "-10+4q=-b...................(1)\r
\n" ); document.write( "\n" ); document.write( "p*q=-3/4\r
\n" ); document.write( "\n" ); document.write( "(-5/2)q=-3/4\r
\n" ); document.write( "\n" ); document.write( "q=3/10\r
\n" ); document.write( "\n" ); document.write( "plug q in (1)
\n" ); document.write( "-10+4(3/10)=b\r
\n" ); document.write( "\n" ); document.write( "(-100+12)/10=b\r
\n" ); document.write( "\n" ); document.write( "-88/10 =b
\n" ); document.write( "-44/5 = b\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );