document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=728905>Question 728905</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help. I am supposed to write the equation in slope-intercept form and I am given the slope as m=-2 and x-intercept of -3. I know the format is y=mx+b but where does the x-intercept go in the equation, and what is the equation? Thanks for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #445638 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=445638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x intercept = -3\r<BR>\n" );
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document.write( "the co-ordinates (-3,0)\r<BR>\n" );
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document.write( "slope =-2\r<BR>\n" );
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document.write( "equation in slope intercept form\r<BR>\n" );
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document.write( "(y-y1)=m(x-x1)\r<BR>\n" );
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document.write( "(y-0)=-2(x-(-3))\r<BR>\n" );
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document.write( "y=2(x+3)\r<BR>\n" );
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document.write( "y=2x+6\r<BR>\n" );
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