document.write( "Question 728883: How do you go about solving this problem?\r
\n" ); document.write( "\n" ); document.write( "A box with no top is constructed from a rectangular piece of cardboard whose length measures 4 inches more than its width. The box is formed by cutting squares from each corner that measure 2 in. on each side and then folding up the sides. If the volume of the box is 64 cubic in., what are the dimensions of the original piece of cardboard?
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Algebra.Com's Answer #445636 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Paper\r
\n" ); document.write( "\n" ); document.write( "let width of box be x
\n" ); document.write( "length of box = x+4\r
\n" ); document.write( "\n" ); document.write( "height will be 2 inches since the cut portion is 2 \"\r
\n" ); document.write( "\n" ); document.write( "width of box = x-4 \"
\n" ); document.write( "length of box = x+4-4= x\r
\n" ); document.write( "\n" ); document.write( "dimensions of new box = x-4, x , 2\"\r
\n" ); document.write( "\n" ); document.write( "Volume = 2x(x-4)\r
\n" ); document.write( "\n" ); document.write( "64=2x^2-8x\r
\n" ); document.write( "\n" ); document.write( "2x^2-8x-64=0
\n" ); document.write( "/2
\n" ); document.write( "x^2-4x-32=0\r
\n" ); document.write( "\n" ); document.write( "x^2-8x+4x-32=0
\n" ); document.write( "x(x-8)+4(x-8)=0\r
\n" ); document.write( "\n" ); document.write( "(x-8)(x+4)=0\r
\n" ); document.write( "\n" ); document.write( "x= -4 OR 8\r
\n" ); document.write( "\n" ); document.write( "ignore negative
\n" ); document.write( "x=width of board 8\"
\n" ); document.write( "length = 12\"
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