document.write( "Question 728839: I need help with writing this equation. \r
\n" ); document.write( "\n" ); document.write( "The question is \"Write the equation of the line through (-3,1) that is parallel to the line whose equation is 2x+y=1.\"\r
\n" ); document.write( "\n" ); document.write( "Please help me on what to do. I do know that I need to re-write equation in slope intercept form, so the equation is y=-2x+1, with a slope of -2. And I know that parallel lines have the same slope. But I don't know what to do from there. Thank you \n" ); document.write( "
Algebra.Com's Answer #445615 by mbmodak(32)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "The given line 2x+y=1 or 2x+y-1=0
\n" ); document.write( "Slope of this line=-coefficient of x/coefficient of y
\n" ); document.write( "slope=-2/1=-2
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\n" ); document.write( "The line passing thr(-3,1) has slope=m=-2
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\n" ); document.write( "using point-slope form
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\n" ); document.write( "y-y_1=m(x-x_1) here y_1=1 &x_1=-3
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\n" ); document.write( "y-1=-2*((x-(-3))
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\n" ); document.write( "y-1=-2x-6
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\n" ); document.write( "y+2x+6-1=0 Changing sides
\n" ); document.write( "2x+y+5=0 slope of this line=-2 & it passes thr(-3,1) i.e.2*(-3)+1+5=0
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\n" ); document.write( "2x+y+5=0 is the equation of line parallel & passing thr(-3,1)
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