document.write( "Question 728830: Steven recently emptied his piggy bank and found he had $5.35 worth of nickels and quarters. He also counted that the number of nickels he had was 9 more than twice the number of quarters. How many of each type of coin did he have? \n" ); document.write( "

Algebra.Com's Answer #445612 by mbmodak(32) $\"\"$ $\"About$

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Let us assume that stevens had x nos of quarters So Nos.of Nickels he owns are 2*x+9
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\n" ); document.write( "as 1 nickel=0.05 $ & I quarter=0.25 $
\n" ); document.write( "Total value in $ is 0.25*x+(2*x+9)*.05 But he had total $ 5.35
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\n" ); document.write( "5.35=0.25*x+(2*x+9)*.05
\n" ); document.write( "5.35=0.25x+2*x*(.05)+9*(.05)
\n" ); document.write( "5.35=0.35*x+0.45
\n" ); document.write( "5.35-0.45=0.35x
\n" ); document.write( "4.9=0.35*x
\n" ); document.write( "4.9/0.35=x
\n" ); document.write( "14=x
\n" ); document.write( "So stevens has 14 nos quarters & (14*2+9) i.e.37 nos ov nickel
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\n" ); document.write( "14*0.25+37*0.05=5.35
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