document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=728706>Question 728706</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x+3y=12<BR>\n" );
document.write( "5x-y=13 \r<BR>\n" );
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document.write( "Solve by substitution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #445576 by </B><A HREF=/tutors/aboutme.mpl?userid=dr8><B>dr8(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dr8><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dr8><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=445576\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First you would take the second equation and move the 5x to the right side by subtracting 5x on both sides. You should now have -y=-5x+13. To make y positive, we need to divide this equation by -1. You should now have y=5x-13. Substitute y=5x-13 in the first equation. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B3%285x-13%29=12 ALIGN=MIDDLE  ALT=\"2x%2B3%285x-13%29=12\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B15x-39=12 ALIGN=MIDDLE  ALT=\"2x%2B15x-39=12\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Add the x values and you have 17x-39=12. Now we need to move the 39 to the right side by adding 39 on both sides. Now you should have <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=17x=51 ALIGN=MIDDLE  ALT=\"17x=51\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Divide 17 on both sides to get x, and you should get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=3 ALIGN=MIDDLE  ALT=\"x=3\"   DISABLED_style= \"max-width:90%; height:auto;\" >. To find y, you would plug x in the second equation. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%283%29-y=13 ALIGN=MIDDLE  ALT=\"5%283%29-y=13\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15-y=13 ALIGN=MIDDLE  ALT=\"15-y=13\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Then move the 15 by subtracting it on both sides to get y by it self. You should now have -y = -2. To find y, divide both sides by -2, and you should get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=2 ALIGN=MIDDLE  ALT=\"y=2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. So x=3 and y=2. I hope this helped! Good luck! </SPAN>\n" );
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