document.write( "Question 728636: Find the amount accumulated to the nearest cent on $700 compounded annually for 3 years at 9 %\r
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document.write( "Formula: A=p(1+R) \n" );
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Algebra.Com's Answer #445549 by ohtheirony(35)![]() ![]() You can put this solution on YOUR website! The equation for exponential growth is \n" ); document.write( " \n" ); document.write( "a=the original starting rate (the compound: $700) \n" ); document.write( "x=percent the rate is increasing annually (depreciation of 9%) \n" ); document.write( "t=amount of time past while the amount is increasing (3 years) \n" ); document.write( " \n" ); document.write( "So, your equation would be... \n" ); document.write( " \n" ); document.write( "A=700(1+.09)^3 (^3 is (1+.09) to the third exponent) \n" ); document.write( "A=700(1.09)^3 \n" ); document.write( "A=700(1.295029) \n" ); document.write( "A=906.5203 \n" ); document.write( " \n" ); document.write( "So, your answer would be $906.52. \n" ); document.write( " \n" ); document.write( "For more on exponential growth and also exponential decay, try this link: \n" ); document.write( "http://www.regentsprep.org/Regents/math/ALGEBRA/AE7/ExpDecayL.htm \n" ); document.write( " |