document.write( "Question 728636: Find the amount accumulated to the nearest cent on $700 compounded annually for 3 years at 9 %\r
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\n" ); document.write( "\n" ); document.write( "Formula: A=p(1+R)
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Algebra.Com's Answer #445549 by ohtheirony(35)\"\" \"About 
You can put this solution on YOUR website!
The equation for exponential growth is \"A=a%281%2Bx%29%5Et\".
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\n" ); document.write( "a=the original starting rate (the compound: $700)
\n" ); document.write( "x=percent the rate is increasing annually (depreciation of 9%)
\n" ); document.write( "t=amount of time past while the amount is increasing (3 years)
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\n" ); document.write( "So, your equation would be...
\n" ); document.write( "\"A=a%281%2Bx%29%5Et\"
\n" ); document.write( "A=700(1+.09)^3 (^3 is (1+.09) to the third exponent)
\n" ); document.write( "A=700(1.09)^3
\n" ); document.write( "A=700(1.295029)
\n" ); document.write( "A=906.5203
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\n" ); document.write( "So, your answer would be $906.52.
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\n" ); document.write( "For more on exponential growth and also exponential decay, try this link:
\n" ); document.write( "http://www.regentsprep.org/Regents/math/ALGEBRA/AE7/ExpDecayL.htm
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