document.write( "Question 728598: A chemist must mix 6 liters of a 30% acid solution with some of an 80% acid solution to get a 50% acid solution to get a 50% acid solution. How many liters of the 80% solution should be used ? \n" ); document.write( "

Algebra.Com's Answer #445536 by checkley79(3341) $\"\"$ $\"About$

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.80X+.30*6=.50(6+X)
\n" ); document.write( ".80X+1.8=3+.50X
\n" ); document.write( ".80X-.50X=3-1.8
\n" ); document.write( ".30X=1.2
\n" ); document.write( "X=1.2/.30
\n" ); document.write( "X=4 LITERS OF THE 80% SOLUTION IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".80*4+.30*6=.50(6+4)
\n" ); document.write( "3.2+1.8=.5*10
\n" ); document.write( "5=5 \n" ); document.write( "

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