document.write( "Question 728604:
\n" ); document.write( "Sonya inherited $ 35,000. She invested some of the money at 2.5% simple interest and the rest at 3.5% simple interest. In the first year, she earned $ 1,075 interest. How many dollard did she earn form her investment at 3.5% interest ?
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Algebra.Com's Answer #445531 by checkley79(3341)\"\" \"About 
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.035X+.025(35,000-X)=1.075
\n" ); document.write( ".035X+875-.025X=1.075
\n" ); document.write( ".010X=1,075-875
\n" ); document.write( ".010X=200
\n" ); document.write( "X=200/.010
\n" ); document.write( "X=20,000 AMOUNT INVESTED @ 3.5%.
\n" ); document.write( "35,000-20,000=15,000 AMOUNT INVESTED @ 2.5%.PROOF:
\n" ); document.write( ".035*20,000+.025*15,000=1,075
\n" ); document.write( "700+375=1,075
\n" ); document.write( "1,075=1,075
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