document.write( "Question 728604:
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document.write( "Sonya inherited $ 35,000. She invested some of the money at 2.5% simple interest and the rest at 3.5% simple interest. In the first year, she earned $ 1,075 interest. How many dollard did she earn form her investment at 3.5% interest ? \n" );
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Algebra.Com's Answer #445531 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .035X+.025(35,000-X)=1.075 \n" ); document.write( ".035X+875-.025X=1.075 \n" ); document.write( ".010X=1,075-875 \n" ); document.write( ".010X=200 \n" ); document.write( "X=200/.010 \n" ); document.write( "X=20,000 AMOUNT INVESTED @ 3.5%. \n" ); document.write( "35,000-20,000=15,000 AMOUNT INVESTED @ 2.5%.PROOF: \n" ); document.write( ".035*20,000+.025*15,000=1,075 \n" ); document.write( "700+375=1,075 \n" ); document.write( "1,075=1,075 \n" ); document.write( " \n" ); document.write( " |