document.write( "Question 728581: Help with a few problems, please.\r
\n" ); document.write( "\n" ); document.write( "1. Solve by completing the square: 2x^2 + x + 2 = 0\r
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\n" ); document.write( "\n" ); document.write( "3. Write a quadratic equation that has integer coefficients and has solutions 4/3 and 6.
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Algebra.Com's Answer #445506 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form

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\n" ); document.write( " \"y=2+x%5E2%2B1+x%2B2\" Start with the given equation
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\n" ); document.write( " \"y-2=2+x%5E2%2B1+x\" Subtract \"2\" from both sides
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\n" ); document.write( " \"y-2=2%28x%5E2%2B%281%2F2%29x%29\" Factor out the leading coefficient \"2\"
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\n" ); document.write( " Take half of the x coefficient \"1%2F2\" to get \"1%2F4\" (ie \"%281%2F2%29%281%2F2%29=1%2F4\").
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\n" ); document.write( " Now square \"1%2F4\" to get \"1%2F16\" (ie \"%281%2F4%29%5E2=%281%2F4%29%281%2F4%29=1%2F16\")
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\n" ); document.write( " \"y-2=2%28x%5E2%2B%281%2F2%29x%2B1%2F16-1%2F16%29\" Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of \"1%2F16\" does not change the equation
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\n" ); document.write( " \"y-2=2%28%28x%2B1%2F4%29%5E2-1%2F16%29\" Now factor \"x%5E2%2B%281%2F2%29x%2B1%2F16\" to get \"%28x%2B1%2F4%29%5E2\"
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\n" ); document.write( " \"y-2=2%28x%2B1%2F4%29%5E2-2%281%2F16%29\" Distribute
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\n" ); document.write( " \"y-2=2%28x%2B1%2F4%29%5E2-1%2F8\" Multiply
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\n" ); document.write( " \"y=2%28x%2B1%2F4%29%5E2-1%2F8%2B2\" Now add \"2\" to both sides to isolate y
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\n" ); document.write( " \"y=2%28x%2B1%2F4%29%5E2%2B15%2F8\" Combine like terms
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\n" ); document.write( " Now the quadratic is in vertex form \"y=a%28x-h%29%5E2%2Bk\" where \"a=2\", \"h=-1%2F4\", and \"k=15%2F8\". Remember (h,k) is the vertex and \"a\" is the stretch/compression factor.
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\n" ); document.write( " Check:
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\n" ); document.write( " Notice if we graph the original equation \"y=2x%5E2%2B1x%2B2\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C2x%5E2%2B1x%2B2%29\" Graph of \"y=2x%5E2%2B1x%2B2\". Notice how the vertex is (\"-1%2F4\",\"15%2F8\").
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\n" ); document.write( " Notice if we graph the final equation \"y=2%28x%2B1%2F4%29%5E2%2B15%2F8\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C2%28x%2B1%2F4%29%5E2%2B15%2F8%29\" Graph of \"y=2%28x%2B1%2F4%29%5E2%2B15%2F8\". Notice how the vertex is also (\"-1%2F4\",\"15%2F8\").
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\n" ); document.write( " So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.
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Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:

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\n" ); document.write( " Starting with the general quadratic
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\n" ); document.write( " \"ax%5E2%2Bbx%2Bc=0\"
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\n" ); document.write( " the general solution using the quadratic equation is:
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\n" ); document.write( " \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"
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\n" ); document.write( " So lets solve \"5%2Ax%5E2-2%2Ax%2B3=0\" ( notice \"a=5\", \"b=-2\", and \"c=3\")
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\n" ); document.write( " \"x+=+%28--2+%2B-+sqrt%28+%28-2%29%5E2-4%2A5%2A3+%29%29%2F%282%2A5%29\" Plug in a=5, b=-2, and c=3
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\n" ); document.write( " \"x+=+%282+%2B-+sqrt%28+%28-2%29%5E2-4%2A5%2A3+%29%29%2F%282%2A5%29\" Negate -2 to get 2
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\n" ); document.write( " \"x+=+%282+%2B-+sqrt%28+4-4%2A5%2A3+%29%29%2F%282%2A5%29\" Square -2 to get 4 (note: remember when you square -2, you must square the negative as well. This is because \"%28-2%29%5E2=-2%2A-2=4\".)
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\n" ); document.write( " \"x+=+%282+%2B-+sqrt%28+4%2B-60+%29%29%2F%282%2A5%29\" Multiply \"-4%2A3%2A5\" to get \"-60\"
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\n" ); document.write( " \"x+=+%282+%2B-+sqrt%28+-56+%29%29%2F%282%2A5%29\" Combine like terms in the radicand (everything under the square root)
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\n" ); document.write( " \"x+=+%282+%2B-+2%2Ai%2Asqrt%2814%29%29%2F%282%2A5%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
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\n" ); document.write( " \"x+=+%282+%2B-+2%2Ai%2Asqrt%2814%29%29%2F%2810%29\" Multiply 2 and 5 to get 10
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\n" ); document.write( " After simplifying, the quadratic has roots of
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\n" ); document.write( " \"x=1%2F5%2Bsqrt%2814%29%2F5%2Ai\" or \"x=1%2F5-sqrt%2814%29%2F5%2Ai\"
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\n" ); document.write( "\n" ); document.write( "\"%28x-x%5B1%5D%29%28x-x%5B2%5D%29\"....if \"x%5B1%5D=4%2F3\" and \"x%5B2%5D=6\", than\r
\n" ); document.write( "\n" ); document.write( "\"%28x-4%2F3%29%28x-6%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-%284%2F3%29x-6x%2B%284%2F3%296\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-%28%284%2F3%29%2B6%29x%2B4%2A2\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-%2822%2F3%29x%2B8\"
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