document.write( "Question 63910This question is from textbook Algebra 1
\n" ); document.write( ": Find two consecutive positive numbers such that the product of the sum and difference of the numbers plus eight is the sum of their squares.
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Algebra.Com's Answer #44549 by venugopalramana(3286)\"\" \"About 
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Find two consecutive positive numbers
\n" ); document.write( "N AND N+1 SAY
\n" ); document.write( "such that the product of the sum(N+N+1=2N+1) and difference(N+1-N=1) of the numbers plus eight
\n" ); document.write( "(2N+1)1+8
\n" ); document.write( "is the sum of their squares[(N^2+(N+1)^2].
\n" ); document.write( "2N+1+8=N^2+(N+1)^2=N^2+N^2+1+2N
\n" ); document.write( "2N^2-8=0
\n" ); document.write( "N^2=8/2=4
\n" ); document.write( "N=+2 0R -2
\n" ); document.write( "HENCE THE 2 NUMBERS ARE
\n" ); document.write( "2 AND 3 .....CHECK...(2+3)(3-2)+8=2^2+3^2.....13=13..OK
\n" ); document.write( "OR
\n" ); document.write( "-2 AND -1..........CHECK.....(-2-1)(-1+2)+8=(-2)^2+(-1)^2...OR....5=5..OK\r
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