document.write( "Question 728393: An Adweek Media/Harris Poll revealed that 44% of US adults in the 18-34 years category think that \"Made in America\" ads boost sales.
\n" ); document.write( "A different Harris Interactive poll showed that 78% of US adults in the 18-34 years category use social media online.
\n" ); document.write( "Suppose that 85% of US adults in the 18-34 years category think that \"Made in America\" ads boost sales or use social media online.
\n" ); document.write( "If a US adult in the 18-34 years category is randomly selected a.
\n" ); document.write( "What is the probability that the person thinks \"Made in America\" ads boost sales AND uses social media on-line & \r
\n" ); document.write( "\n" ); document.write( "b. What is the probability that the person thinks that \"Made in America ads boost sales given that the person does not use social media on-line?
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Algebra.Com's Answer #445470 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A) 44% of US adults in the 18-34 years category think that \"Made in America\" ads boost sales.
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\n" ); document.write( "B) 78% of US adults in the 18-34 years category use social media online.
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\n" ); document.write( "Suppose that 85% of US adults in the 18-34 years category think that \"Made in America\" ads boost sales OR use social media online.
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\n" ); document.write( "If a US adult in the 18-34 years category is randomly selected
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\n" ); document.write( "a. What is the probability that the person thinks \"Made in America\" ads boost sales AND uses social media on-line &
\n" ); document.write( "Ans: P(A AND B) = P(A)+P(B)-P(A or B) = 0.44+0.78-0.85 = 0.37
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\n" ); document.write( "b. What is the probability that the person thinks that \"Made in America ads boost sales given that the person does not use social media on-line?
\n" ); document.write( "P(A | B) = P(A and B)/P(B) = 0.37/0.78 = 0.4744
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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