document.write( "Question 728460: how many liters of a 30% saline solution must be mixed with a 40% saline solution to obtain 25 liters of a 32% saline solution? \n" ); document.write( "
Algebra.Com's Answer #445418 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
how many liters of a 30% saline solution must be mixed with a 40% saline solution to obtain 25 liters of a 32% saline solution?
\n" ); document.write( ".
\n" ); document.write( "Let x = amount (liters) of 30%
\n" ); document.write( "then
\n" ); document.write( "25-x = amount (liters) of 40%
\n" ); document.write( ".
\n" ); document.write( ".30x + .40(25-x) = .32(25)
\n" ); document.write( ".30x + 10-.40x = 8
\n" ); document.write( "10-.10x = 8
\n" ); document.write( "-.10x = -2
\n" ); document.write( "x = 20 liters (of 30%)
\n" ); document.write( ".
\n" ); document.write( "amount of 40%:
\n" ); document.write( "25-x = 25-20 = 5 liters \n" ); document.write( "
\n" );