document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63899>Question 63899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation. {How many grams of 4% salt solution must be mixed with 80 grams of 11% salt solution to make an 8% salt solution?} </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44539 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44539\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation. {How many grams of 4% salt solution must be mixed with 80 grams of 11% salt solution to make an 8% salt solution?}<BR>\n" );
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document.write( "Let amount of 4% solution be \"x\" ; amount of salt in it is 0.04x grams<BR>\n" );
document.write( "Amount of 11% solution is 80 grams; amount of salt in it is 0.11(80)=8.8 grms.<BR>\n" );
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document.write( "EQUATIOn:<BR>\n" );
document.write( "salt + salt = 0.08(80+x)<BR>\n" );
document.write( "0.04x+8.8=6.4+0.08x<BR>\n" );
document.write( "-0.04x=-2.4<BR>\n" );
document.write( "x=60 (amount of 4% solution that must be mixed)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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