document.write( "Question 728367: Find the polynomial equation with real coefficients that has the given roots?\r
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\n" ); document.write( "\n" ); document.write( "i think that this is a reverse on a quadratic equation, but i have no notes on the procedure...can you please help
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Algebra.Com's Answer #445389 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
x = 3 - i (given) or x = 3 + i (all complex roots come in conjugate pairs)\r
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\n" ); document.write( "\n" ); document.write( "x - 3 = -i or x - 3 = i\r
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\n" ); document.write( "\n" ); document.write( "(x - 3)^2 = (-i)^2 or (x - 3)^2 = i^2\r
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\n" ); document.write( "\n" ); document.write( "(x - 3)^2 = i^2 or (x - 3)^2 = i^2\r
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\n" ); document.write( "\n" ); document.write( "(x - 3)^2 = i^2\r
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\n" ); document.write( "\n" ); document.write( "(x - 3)^2 = -1\r
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\n" ); document.write( "\n" ); document.write( "(x - 3)^2 + 1 = 0 ----> Equation in Vertex Form: \"y+=+%28x-3%29%5E2+%2B+1\"\r
\n" ); document.write( "\n" ); document.write( "(x - 3)(x - 3) + 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 6x + 9 + 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 6x + 10 = 0 ----> Equation in Standard Form: \"y+=+x%5E2+-+6x+%2B+10\"
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