document.write( "Question 728367: Find the polynomial equation with real coefficients that has the given roots?\r
\n" );
document.write( "\n" );
document.write( "3 - i\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "i think that this is a reverse on a quadratic equation, but i have no notes on the procedure...can you please help \n" );
document.write( "
Algebra.Com's Answer #445389 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! x = 3 - i (given) or x = 3 + i (all complex roots come in conjugate pairs)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x - 3 = -i or x - 3 = i\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x - 3)^2 = (-i)^2 or (x - 3)^2 = i^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x - 3)^2 = i^2 or (x - 3)^2 = i^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x - 3)^2 = i^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x - 3)^2 = -1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x - 3)^2 + 1 = 0 ----> Equation in Vertex Form: \n" ); document.write( "\n" ); document.write( "(x - 3)(x - 3) + 1 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 6x + 9 + 1 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 6x + 10 = 0 ----> Equation in Standard Form: |