document.write( "Question 728231: 10 dollars in bank, 11 more nickels than dimes, how many coins in bank? \n" ); document.write( "

Algebra.Com's Answer #445362 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "You could have 1 dime, 12 nickels and 930 pennies.\r\n" );
document.write( "You could have 9 quarters, 24 dimes, 35 nickels and 360 pennies.\r\n" );
document.write( "You could have 33 quarters, 8 dimes, and 19 nickels.\r\n" );
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document.write( "Many, many, many ways!\r\n" );
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document.write( "Notice thet you didn't say anything about not having other coins\r\n" );
document.write( "besides nickels and dimes.  You just said there are 11 more nickels \r\n" );
document.write( "than dimes.  That is true about all those solutions above, and\r\n" );
document.write( "there are many other possibilities.  \r\n" );
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document.write( "Be sure to state if the bank only contains nickels and dimes.\r\n" );
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document.write( "If you meant that there are only nickels and dimes, then\r\n" );
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document.write( "Let d = the number of dimes\r\n" );
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document.write( "Then the number of nickels is d+11\r\n" );
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document.write( "The equation comes from\r\n" );
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document.write( "             \r\n" );
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document.write( "          0.05(d+11) + 0.10(d) = 10.00\r\n" );
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document.write( "Clear of decimals by multiplying all the decimals by 100.\r\n" );
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document.write( "                 5(d+11) + 10d = 1000\r\n" );
document.write( "                 5d + 55 + 10d = 1000\r\n" );
document.write( "                      15d + 55 = 1000\r\n" );
document.write( "                           15d = 945\r\n" );
document.write( "                             d = 63\r\n" );
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document.write( "So there are 63 dimes and \r\n" );
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document.write( "The number of nickels is d+11 = 63+11 = 74 nickels.\r\n" );
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document.write( "Edwin

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