document.write( "Question 728181: I have an extra credit sheet, 25 problems similar to these two. Can someone help with an explanation to solve both? Appreciation is unlimited.\r
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document.write( "Use the empirical, otherwise known as the 68 - 95 - 99.7 rule.\r
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document.write( "1) Distribution is normal. Mean is 10, Standard Deviation is 2, find the percentage of values in the distribution: BELOW 10\r
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document.write( "2) Mean is 12, Standard Deviation is 3, find percentage of values in the distribution: ABOVE 18. \n" );
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Algebra.Com's Answer #445356 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "68 percent is within 1 standard deviation of the mean, and 95 percent is within 2 standard deviations of the mean. Normal distribution means that half of the data is above the mean and half below.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So for problem 2, if the mean is 12 and the sd is 3, then 18 is exactly 2 standard deviations above the mean. We know that 95 percent of the data is within 2 standard deviations of the mean, so half of 95 percent, namely 47.5% is within 2 sd below the mean and the other 47.5% is within 2 sd above the mean. So, adding it all up, 50% is below the mean, then 47.5 is 2 sd above the mean. Hence 97.5% of the data is less than or equal to 18. Therefore 1 - 0.975 = 0.025 or 2.5% is greater than or equal to 18.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |