document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=728162>Question 728162</A>: <I><SPAN STYLE=\"word-break: break-all;\"> elliot has 32 yards of fencing. He wants to fence in a garden that is 6 yards wide. What is he largest rectangle he could make? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #445329 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=445329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is only a matter of accounting for perimeter, which must be 32 yards.\r<BR>\n" );
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document.write( "Let the unknown length be p.  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A6%2B2%2Ap=32 ALIGN=MIDDLE  ALT=\"2%2A6%2B2%2Ap=32\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Solving simply for p,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2p=32-12 ALIGN=MIDDLE  ALT=\"2p=32-12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2p=20 ALIGN=MIDDLE  ALT=\"2p=20\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p=10 ALIGN=MIDDLE  ALT=\"p=10\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The rectangular garden would be 6 by 10 yards. </SPAN>\n" );
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