document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=728099>Question 728099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of 20% and 60% acids must be mixed in order to make 12 liters of a 55% acid solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #445304 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=445304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many liters of 20% and 60% acids must be mixed in order to make 12 liters of a 55% acid solution<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.20x + 0.60(12-x) = 0.55*12<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "20x + 60*12-60x = 55*12<BR>\n" );
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document.write( "-40x = -5*12<BR>\n" );
document.write( "x = 12/8<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = 3/2 liters (amt. of 20% solution needed)<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );