document.write( "Question 727984: a 20 liter container is filled with pure acid. five liters of the mixture are drawn off and replaced with water and so on until 5 drawing and 5 replacements have been made. find the amount of acid in the final mixture \n" ); document.write( "
Algebra.Com's Answer #445295 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
After 1st replacement,
\n" ); document.write( "there is \"+20+-+5+=+15+\" liters of acid in 20 liters of solution
\n" ); document.write( "-------------------
\n" ); document.write( "After 2nd replacement
\n" ); document.write( "There is \"+5%2A%28+15%2F20+%29+=+15%2F4+\" liters of acid removed
\n" ); document.write( "There is \"+15+-+15%2F4+=+45%2F4+\" liters of acid left
\n" ); document.write( "\"+11.25+\" liters left
\n" ); document.write( "--------------------
\n" ); document.write( "After 3rd replacement
\n" ); document.write( "There is \"+5%2A%28+%28+45%2F4%29%2F20+%29++=+5%2A%2845%2F80%29+\"
\n" ); document.write( "\"+45%2F16+\" liters of acid removed
\n" ); document.write( "There is \"+45%2F4+-+45%2F16+=+135%2F16+\" liters of acid left
\n" ); document.write( "\"+8.4375+\" liters left
\n" ); document.write( "---------------------
\n" ); document.write( "After 4th replacement
\n" ); document.write( "There is \"+5%2A%28+%28+135%2F16+%29+%2F20+%29+=+135%2F64+\" liters
\n" ); document.write( "of acid removed
\n" ); document.write( "There is \"+135%2F16+-+135%2F64+=+405%2F64+\" liters of acid left
\n" ); document.write( "\"+6.328125+\" liters left
\n" ); document.write( "-----------------------
\n" ); document.write( "After 5th replacement
\n" ); document.write( "There is \"+5%2A%28+%28+405%2F64+%29+%2F20+%29+=+405%2F256+\" liters of acid removed
\n" ); document.write( "There is \"+405%2F64+-+405%2F256+=+1215%2F256+\" liters of acid left
\n" ); document.write( "-------------------------
\n" ); document.write( "\"+1215%2F256+=+4.7461+\" liters of acid left
\n" ); document.write( "Hope I got it!\r
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