document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63882>Question 63882</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base of an isosceles triangle is 8 in. less than the length of the equal sides.  If the perimeter of the triangle is 28 in., find the length of each of the sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44528 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=S+S+B<BR>\n" );
document.write( "28=S+S+(S-8)<BR>\n" );
document.write( "28=3S-8<BR>\n" );
document.write( "3S=28+8<BR>\n" );
document.write( "3S==36<BR>\n" );
document.write( "S=36/3<BR>\n" );
document.write( "S=12 SOLUTION<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "28=12+12+(12-8)<BR>\n" );
document.write( "28=24+4<BR>\n" );
document.write( "28=28\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );