document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=727445>Question 727445</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this.\r<BR>\n" );
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document.write( "1n(x - 6) + 1n(x+5)=1n -42\r<BR>\n" );
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document.write( "Possible answers:\r<BR>\n" );
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document.write( "A) -8,9<BR>\n" );
document.write( "B) -9,8<BR>\n" );
document.write( "C) imaginary<BR>\n" );
document.write( "D) None<BR>\n" );
document.write( "E) 8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #445235 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=445235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1n(x - 6) + 1n(x+5)=1n -42<BR>\n" );
document.write( "ln[(x-6)(x+5)]=ln(-42)<BR>\n" );
document.write( "(x-6)(x+5)=-42<BR>\n" );
document.write( "x^2-x-30=-42<BR>\n" );
document.write( "x^2-x+12=0<BR>\n" );
document.write( "b^2-4ac=1-4*1*12<0<BR>\n" );
document.write( "Therefore, there are no real answers:(answer C)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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