document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=727834>Question 727834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the speed of the plane is still weather? \r<BR>\n" );
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document.write( "As in \"A jet plane flies 5 hours west with a 60 MPH headwind. The plane returns east with a tailwind and the round trip took 9 hours of flying\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #445203 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=445203\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance = rate x time.  The plane travels the same distance both ways.  So the original distance = the return distance.<P><BR>\n" );
document.write( "For the original distance, the plane flew at its speed (x) minus 60 MPH (the plane is traveling against the headwind, so the headwind subtracts from the plane's speed). D = (x-60) * 5<P><BR>\n" );
document.write( "For the return trip the tailwind adds to the speed.  The round trip was 9 hours, and the original trip took 5 hours, so the return trip took 9-5 = 4 hours.  D = (x+60) * 4<P><BR>\n" );
document.write( "Those distances are equal.  (x-60)*5 = (x+60)*4 <P><BR>\n" );
document.write( "5x - 300 = 4x + 240<P><BR>\n" );
document.write( "x = 540 MPH<BR>\n" );
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