document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=727748>Question 727748</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve using N as the variable:<BR>\n" );
document.write( " 3 consecutive integers in which 4 times the sum of the first 2 is the same as 6 times the third? \r<BR>\n" );
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document.write( "please and thank you.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #445173 by </B><A HREF=/tutors/aboutme.mpl?userid=mbmodak><B>mbmodak(32)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mbmodak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=445173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let (n-1) , n ,(n+1) be three con integers<BR>\n" );
document.write( "Now 4(n-1)+4n = 6(n+1)  as per given condition<BR>\n" );
document.write( "4n-4+4n = 6n+6<BR>\n" );
document.write( "4n-4+4n-6n+4 = 6n+6-6n+4<BR>\n" );
document.write( "8n-6n = 10<BR>\n" );
document.write( "2n=10<BR>\n" );
document.write( "n=10/2=5\r<BR>\n" );
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document.write( "the con integers are then (5-1) ,5, (5+1) or 4 , 5 ,6\r<BR>\n" );
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document.write( "[ 4*4+5*4=6*6 ]<BR>\n" );
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