document.write( "Question 727727: 2-log3x = log(x/12)
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Algebra.Com's Answer #445162 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
2-log3x = log(x/12)
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\n" ); document.write( "2 - [log(3)+log(x)] = log(x)-log(12)
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\n" ); document.write( "2 - log(3)-log(x) = log(x) - log(12)
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\n" ); document.write( "2 - log(3) = 2log(x) - log(12)
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\n" ); document.write( "log(x^2) = 2 - log(3)+log(12)
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\n" ); document.write( "log(x^2) = 2 + log(12/3)
\n" ); document.write( "log(x^2) = 2.6021
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\n" ); document.write( "x^2 = 10*2.6021
\n" ); document.write( "x = 1.4537
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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