document.write( "Question 727402: convert 287 to base 3 \n" ); document.write( "
Algebra.Com's Answer #445088 by Edwin McCravy(20055)\"\" \"About 
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287 to base 3
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document.write( "We divide 3 into 287, getting 95 with remainder 2. We write the \r\n" );
document.write( "quotient 95 below and the remainder 2 out to the side, like this:\r\n" );
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document.write( "3)287\r\n" );
document.write( "   95 R=2\r\n" );
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document.write( "Under that, we divide 3 into 95, getting 31 with remainder 2. We \r\n" );
document.write( "write the quotient 31 below and the remainder 2 out to the side, \r\n" );
document.write( "like this:\r\n" );
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document.write( "3)287\r\n" );
document.write( " 3)95 R=2\r\n" );
document.write( "   31 R=2\r\n" );
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document.write( "Under that, we divide 3 into 31, getting 10 with remainder 1.  We\r\n" );
document.write( "write the quotient 10 below and the remainder 1 out to the side,\r\n" );
document.write( "like this:\r\n" );
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document.write( "3)287\r\n" );
document.write( " 3)95 R=2\r\n" );
document.write( " 3)31 R=2\r\n" );
document.write( "   10 R=1\r\n" );
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document.write( "Under that, we divide 3 into 10, getting 13 with remainder 1.  We\r\n" );
document.write( "write the quotient 3 below and the remainder 1 out to the side,\r\n" );
document.write( "like this:\r\n" );
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document.write( "3)287\r\n" );
document.write( " 3)95 R=2\r\n" );
document.write( " 3)31 R=2\r\n" );
document.write( " 3)10 R=1\r\n" );
document.write( "    3 R=1\r\n" );
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document.write( "Under that, we divide 3 into 3, getting 1 with remainder 0.  We\r\n" );
document.write( "write the quotient 1 below and the remainder 0 out to the side,\r\n" );
document.write( "like this:\r\n" );
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document.write( "3)287\r\n" );
document.write( " 3)95 R=2\r\n" );
document.write( " 3)31 R=2\r\n" );
document.write( " 3)10 R=1\r\n" );
document.write( "  3)3 R=1\r\n" );
document.write( "    1 R=0\r\n" );
document.write( "   \r\n" );
document.write( "Under that, we divide 3 into 1, getting 0 with remainder 1.  We\r\n" );
document.write( "write the quotient 0 below and the remainder 1 out to the side,\r\n" );
document.write( "like this:\r\n" );
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document.write( "3)287\r\n" );
document.write( " 3)95 R=2\r\n" );
document.write( " 3)31 R=2\r\n" );
document.write( " 3)10 R=1\r\n" );
document.write( "  3)3 R=1\r\n" );
document.write( "  3)1 R=0\r\n" );
document.write( "    0 R=1\r\n" );
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document.write( "We are done since the last quotient was 0.\r\n" );
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document.write( "To get the number 287 in base 3, we write\r\n" );
document.write( "the remainders from bottom to top:\r\n" );
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document.write( "287 in base ten equals 101122 in base 3.\r\n" );
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document.write( "Edwin
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