document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=727305>Question 727305</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The temperature has been as high as 89 and low as 43. Find values for a and b so that the solution to |x-a|_< b expresses the temperatures in terms of x. (The phone won't allow me to input less than or equal to, but that's what comes after the absolute value.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #445051 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=445051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The temperature has been as high as 89 and low as 43. Find values for a and b so that the solution to |x-a|_< b expresses the temperatures in terms of x. <BR>\n" );
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document.write( "Find the midpoint of the interval.<BR>\n" );
document.write( "(89+43)/2 = 66<BR>\n" );
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document.write( "Find the distance to an endpoint.<BR>\n" );
document.write( "89-66 = 23<BR>\n" );
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document.write( "|x-66| <= 23<BR>\n" );
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document.write( "Ans: a = 66 ; b = 23<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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