document.write( "Question 63838: Rogers age is 1 1/3 times Stevens age. Eight years ago, Rogers age was twice Stevens age. Find Rogers age. \n" ); document.write( "
Algebra.Com's Answer #44499 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Rogers age is 1 1/3 times Stevens age. Eight years ago, Rogers age was twice Stevens age. Find Rogers age. \n" ); document.write( "------------------ \n" ); document.write( "Ages NOW: \n" ); document.write( "Let Steven's age be \"x\". \n" ); document.write( "Roger is now (4/3)x yrs old. \n" ); document.write( "-------------------- \n" ); document.write( "Eight years AGO: \n" ); document.write( "Steven was \"x-8\" years old. \n" ); document.write( "Roger was (4/3)x-8 years old. \n" ); document.write( "-------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "(4/3)x-8=2(x-8) \n" ); document.write( "(4/3)x-8=2x-16 \n" ); document.write( "(4/3)x-(6/3)x=8-16 \n" ); document.write( "(-2/3) x =-8 \n" ); document.write( "x=12 \n" ); document.write( "Roger's age NOW is (4/3)(12)=16 years \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |