document.write( "Question 63838: Rogers age is 1 1/3 times Stevens age. Eight years ago, Rogers age was twice Stevens age. Find Rogers age. \n" ); document.write( "
Algebra.Com's Answer #44499 by stanbon(75887)\"\" \"About 
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Rogers age is 1 1/3 times Stevens age. Eight years ago, Rogers age was twice Stevens age. Find Rogers age.
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\n" ); document.write( "Ages NOW:
\n" ); document.write( "Let Steven's age be \"x\".
\n" ); document.write( "Roger is now (4/3)x yrs old.
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\n" ); document.write( "Eight years AGO:
\n" ); document.write( "Steven was \"x-8\" years old.
\n" ); document.write( "Roger was (4/3)x-8 years old.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "(4/3)x-8=2(x-8)
\n" ); document.write( "(4/3)x-8=2x-16
\n" ); document.write( "(4/3)x-(6/3)x=8-16
\n" ); document.write( "(-2/3) x =-8
\n" ); document.write( "x=12
\n" ); document.write( "Roger's age NOW is (4/3)(12)=16 years
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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