document.write( "Question 727081:
\n" ); document.write( "Last year, Lena had $10,000 to invest. She invested some of it in an account that paid 8% simple interest per year, and she invested the rest in an account that paid 5% simple interest per year. After one year, she received a total of $770 in interest. How much did she invest in each account?
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Algebra.Com's Answer #444989 by checkley79(3341)\"\" \"About 
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.08X+.05(10,000-X)=770
\n" ); document.write( ".08X+500-.05X=770
\n" ); document.write( ".03X=770-500
\n" ); document.write( ".03X=270
\n" ); document.write( "X=270/.03
\n" ); document.write( "X=9,000 AMOUNT INVESTED @ 8%.
\n" ); document.write( "10,000-9,000=1,000 AMOUNT INVESTED @ 5%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".08*9,000+.05*10,000=770
\n" ); document.write( "720+50=770
\n" ); document.write( "770=770
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