document.write( "Question 727128: How many liters of a 10% solution of acid should be mixed with 60% solution of acid to obtain 20 liters of 50% solution?\r
\n" ); document.write( "\n" ); document.write( "I need to solve this using systems of Equations, but I have no idea how to set it up. I have so far stated that x = 10% solution and that y = 60% solution
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Algebra.Com's Answer #444967 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How many liters of a 10% solution of acid should be mixed with 60% solution of acid to obtain 20 liters of 50% solution?
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\n" ); document.write( "Quantity Eq: t + s = 20 liters
\n" ); document.write( "Acid Eq:: 10t+60s = 50*20
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\n" ); document.write( "Modify:
\n" ); document.write( "6t + 6s = 6*20
\n" ); document.write( "t + 6s = 5*20
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\n" ); document.write( "5t = 1*20
\n" ); document.write( "t = 4 liters (amt. of 10% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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