document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=727123>Question 727123</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "A chemist needs to produce a 60% acid mixture. She has 25% strength solution and 80% strength solution on hand.<BR>\n" );
document.write( "Rounding to the nearest thousandth (3 decimal places; nearest mL), how many liters of 80% solution does she add to create 1 liter of the 60% strength mixture?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444964 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444964\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .80x+.25(1-x)=.60*1<BR>\n" );
document.write( ".80x+.25-.25x=.60<BR>\n" );
document.write( ".55x=.60-.25<BR>\n" );
document.write( ".55x=.35<BR>\n" );
document.write( "x=.35/.55<BR>\n" );
document.write( "x=.636 liters of 80% solution is used.<BR>\n" );
document.write( "1-.636=.364 liters of 25% solution is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".80*.636+.25*.364=.60<BR>\n" );
document.write( ".51+.09=.60<BR>\n" );
document.write( ".60=.60 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );