document.write( "Question 727112: The Nielsen Company reported that children between the ages of 2 and 5 watch an average of 25 hours of television per week. Assume the variable is normally distributed and the standard deviation is 3 hours. If a group of 20 children between the ages of 2 and 5 are randomly selected, find the probability that the mean of the number of hours they watch television will be greater than 26.3 hours. \n" ); document.write( "
Algebra.Com's Answer #444962 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The Nielsen Company reported that children between the ages of 2 and 5 watch an average of 25 hours of television per week. Assume the variable is normally distributed and the standard deviation is 3 hours. If a group of 20 children between the ages of 2 and 5 are randomly selected, find the probability that the mean of the number of hours they watch television will be greater than 26.3 hours. \n" ); document.write( "------------------ \n" ); document.write( "z(26.3) = (26.3-25)/[3/sqrt(20)] = 1.9379 \n" ); document.write( "P(z > 26.3) = P(z> 1.9379) = 0.0263 \n" ); document.write( "--- \n" ); document.write( "If you use the t-distribution you will get: \n" ); document.write( "P(t > 26.3) = tcdf(1.9379,100,19) = 0.0338 \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |