document.write( "Question 726993: \r
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\n" ); document.write( "\n" ); document.write( "A total of $4100 is invested into two accounts paying 3% and 5% annual interest. In one year the combined interest on the accounts is $177.\r
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Algebra.Com's Answer #444926 by checkley79(3341)\"\" \"About 
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.05x+.03(4,100-x)=177
\n" ); document.write( ".05x+123-.03x=177
\n" ); document.write( ".02x=177-123
\n" ); document.write( ".02x=54
\n" ); document.write( "x=54/.02
\n" ); document.write( "x=$2,700 was invested @ 5%.
\n" ); document.write( "4,100-2,700=$1,400 was invested @ 3%
\n" ); document.write( "Proof:
\n" ); document.write( ".05*2,700+.03*1,400=177
\n" ); document.write( "135+42=177
\n" ); document.write( "177=177
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