document.write( "Question 726993: \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "A total of $4100 is invested into two accounts paying 3% and 5% annual interest. In one year the combined interest on the accounts is $177.\r
\n" );
document.write( "\n" );
document.write( "Find the amount invested at 3%. \n" );
document.write( "
Algebra.Com's Answer #444926 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .05x+.03(4,100-x)=177 \n" ); document.write( ".05x+123-.03x=177 \n" ); document.write( ".02x=177-123 \n" ); document.write( ".02x=54 \n" ); document.write( "x=54/.02 \n" ); document.write( "x=$2,700 was invested @ 5%. \n" ); document.write( "4,100-2,700=$1,400 was invested @ 3% \n" ); document.write( "Proof: \n" ); document.write( ".05*2,700+.03*1,400=177 \n" ); document.write( "135+42=177 \n" ); document.write( "177=177 \n" ); document.write( " |