document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=726959>Question 726959</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle has perimeter 56cm. if 4 cm is taken from the length and added to the width, the rectangle becomes a square. Find the dimensions of the original rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #444908 by </B><A HREF=/tutors/aboutme.mpl?userid=W3L><B>W3L(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=W3L><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=444908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let length and width = L and W.\r<BR>\n" );
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document.write( "from statement \"A rectangle has perimeter 56 cm. If 4 cm is taken from the length and added to the width, the rectangle becomes a square\", you can deduce<BR>\n" );
document.write( "2L + 2W = 56 ( its sides make up its perimeter )\r<BR>\n" );
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document.write( "L - 4 = W + 4\r<BR>\n" );
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document.write( "L = W + 8<BR>\n" );
document.write( "sub L = W + 8 into 2L + 2W = 56\r<BR>\n" );
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document.write( "2 ( W + 8 ) + 2W = 56<BR>\n" );
document.write( "2W + 16 + 2W = 56<BR>\n" );
document.write( "4W = 40<BR>\n" );
document.write( "W = 10\r<BR>\n" );
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document.write( "sub W = 10 into L = W + 8<BR>\n" );
document.write( "L = 10 + 8 = 18\r<BR>\n" );
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document.write( "original dimensions of rectangle, length = 18cm and width = 10cm </SPAN>\n" );
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